लीनियर एलजेब्रा उदाहरण

$[\begin{array}{c} 1 & 2 \\ 3 & 4 \end{array}]$

चरण 1

Perform the row operation $R_{2} = R_{2} - 3 R_{1}$ to make the entry at $2, 1$ a $0$ .

और स्टेप्स के लिए टैप करें…

चरण 1.1

Perform the row operation $R_{2} = R_{2} - 3 R_{1}$ to make the entry at $2, 1$ a $0$ .

$[\begin{array}{c} 1 & 2 \\ 3 - 3 \cdot 1 & 4 - 3 \cdot 2 \end{array}]$

चरण 1.2

$R_{2}$ को सरल करें.

$[\begin{array}{c} 1 & 2 \\ 0 & - 2 \end{array}]$

चरण 2

Multiply each element of $R_{2}$ by $- \frac{1}{2}$ to make the entry at $2, 2$ a $1$ .

और स्टेप्स के लिए टैप करें…

चरण 2.1

Multiply each element of $R_{2}$ by $- \frac{1}{2}$ to make the entry at $2, 2$ a $1$ .

$[\begin{array}{c} 1 & 2 \\ - \frac{1}{2} \cdot 0 & - \frac{1}{2} \cdot - 2 \end{array}]$

चरण 2.2

$R_{2}$ को सरल करें.

$[\begin{array}{c} 1 & 2 \\ 0 & 1 \end{array}]$

चरण 3

Perform the row operation $R_{1} = R_{1} - 2 R_{2}$ to make the entry at $1, 2$ a $0$ .

और स्टेप्स के लिए टैप करें…

चरण 3.1

Perform the row operation $R_{1} = R_{1} - 2 R_{2}$ to make the entry at $1, 2$ a $0$ .

$[\begin{array}{c} 1 - 2 \cdot 0 & 2 - 2 \cdot 1 \\ 0 & 1 \end{array}]$

चरण 3.2

$R_{1}$ को सरल करें.

$[\begin{array}{c} 1 & 0 \\ 0 & 1 \end{array}]$